1. kbz1960's Avatar
    Twisted?
    anon(9208252) likes this.
    03-17-15 07:00 AM
  2. kbz1960's Avatar
    Loser?
    anon(9208252) and Carjackd like this.
    03-17-15 07:00 AM
  3. kbz1960's Avatar
    Existing?
    anon(9208252) and Carjackd like this.
    03-17-15 07:00 AM
  4. JamBueree's Avatar
    We do exist.
    kbz1960 and anon(9208252) like this.
    03-17-15 07:35 AM
  5. misterabrasive's Avatar
    For starters I'm three!
    Probably 3 too many!


    Posted with my Z10 on Verizon 10.2.1.3253
    kbz1960, 3MIKE and anon(9208252) like this.
    03-17-15 07:36 AM
  6. kbz1960's Avatar
    We do exist.
    You're just fooling me.
    anon(9208252) likes this.
    03-17-15 07:48 AM
  7. anon(9208252)'s Avatar
    You're just fooling me.
    I'm just a fool

    Passport SQW100-1/10.3.1.2582
    03-17-15 08:04 AM
  8. misterabrasive's Avatar
    I'm just a fool

    Passport SQW100-1/10.3.1.2582
    Thanks for clarifying what we already knew! :-D

    Posted with my Z10 on Verizon 10.2.1.3253
    03-17-15 08:08 AM
  9. anon(9208252)'s Avatar
    Thanks for clarifying what we already knew! :-D

    Posted with my Z10 on Verizon 10.2.1.3253
    Thanks, who are you anyways

    Passport SQW100-1/10.3.1.2582
    kbz1960 and Goldboot02 like this.
    03-17-15 08:19 AM
  10. 3MIKE's Avatar
    Probably 3 too many!


    Posted with my Z10 on Verizon 10.2.1.3253
    Three's company !
    anon(9208252) and Goldboot02 like this.
    03-17-15 08:20 AM
  11. misterabrasive's Avatar
    Three's company !
    Bad company! :-D

    Posted with my Z10 on Verizon 10.2.1.3253
    03-17-15 08:23 AM
  12. misterabrasive's Avatar
    Thanks, who are you anyways

    Passport SQW100-1/10.3.1.2582
    I'm not sure. I'm certain someone will remind me.

    Posted with my Z10 on Verizon 10.2.1.3253
    kbz1960 and anon(9208252) like this.
    03-17-15 08:24 AM
  13. misterabrasive's Avatar
    Thanks, who are you anyways

    Passport SQW100-1/10.3.1.2582
    I just remembered. I'm your money! And guess what? I'm gone! :-D

    Posted with my Z10 on Verizon 10.2.1.3253
    03-17-15 08:26 AM
  14. JamBueree's Avatar
    You're just fooling me.
    Well if you take the square root of pi and multiply it to the number of "members" we have in this "group" then you should get the smaller angle or a right triangle, then using the 180 - (90 + [✓Pi x members]) you get all three angles and assuming that one of the sides is 2cm because of the amount of adjectives in the thread title, you'll be able to fine one of the sides by using cosine rule and then you can find the last one using Pythagoras theorem. One you have the complete triangle you will notice the illuminati eye inside of it staring into your soul. The reason being is that you exist and it knows of your presence.
    Therefore, we all do exist.
    03-17-15 08:27 AM
  15. misterabrasive's Avatar
    Well if you take the square root of pi and multiply it to the number of "members" we have in this "group" then you should get the smaller angle or a right triangle, then using the 180 - (90 + [✓Pi x members]) you get all three angles and assuming that one of the sides is 2cm because of the amount of adjectives in the thread title, you'll be able to fine one of the sides by using cosine rule and then you can find the last one using Pythagoras theorem. One you have the complete triangle you will notice the illuminati eye inside of it staring into your soul. The reason being is that you exist and it knows of your presence.
    Therefore, we all do exist.
    Your mathematical skills are astounding! You're wrong! :-D

    Posted with my Z10 on Verizon 10.2.1.3253
    03-17-15 08:29 AM
  16. Carjackd's Avatar
    I'm just a fool

    Passport SQW100-1/10.3.1.2582
    *crickets*

    Posted via my Canadian Passport
    kbz1960 and anon(9208252) like this.
    03-17-15 08:34 AM
  17. Carjackd's Avatar
    Your mathematical skills are astounding! You're wrong! :-D

    Posted with my Z10 on Verizon 10.2.1.3253
    Don't sugar coat it!

    Posted via my Canadian Passport
    03-17-15 08:34 AM
  18. kbz1960's Avatar
    Well if you take the square root of pi and multiply it to the number of "members" we have in this "group" then you should get the smaller angle or a right triangle, then using the 180 - (90 + [✓Pi x members]) you get all three angles and assuming that one of the sides is 2cm because of the amount of adjectives in the thread title, you'll be able to fine one of the sides by using cosine rule and then you can find the last one using Pythagoras theorem. One you have the complete triangle you will notice the illuminati eye inside of it staring into your soul. The reason being is that you exist and it knows of your presence.
    Therefore, we all do exist.
    Now that's exciting! Or confusing.
    anon(9208252) and Carjackd like this.
    03-17-15 08:47 AM
  19. Carjackd's Avatar
    Now that's exciting! Or confusing.
    I'm gunna roll with the later

    Posted via my Canadian Passport
    03-17-15 09:13 AM
  20. anon(9208252)'s Avatar
    I'm gunna roll with the later

    Posted via my Canadian Passport
    Well you always did roll a little *****

    Passport SQW100-1/10.3.1.2582
    kbz1960, Goldboot02 and Carjackd like this.
    03-17-15 12:29 PM
  21. kbz1960's Avatar
    Well you always did roll a little *****

    Passport SQW100-1/10.3.1.2582
    Funny?
    anon(9208252) and Carjackd like this.
    03-17-15 12:38 PM
  22. anon(9208252)'s Avatar
    Funny?
    That's one way to put it.

    Passport SQW100-1/10.3.1.2582
    kbz1960 and Carjackd like this.
    03-17-15 12:39 PM
  23. kbz1960's Avatar
    That's one way to put it.

    Passport SQW100-1/10.3.1.2582
    Just watch where you're putting it!
    03-17-15 12:40 PM
  24. anon(9208252)'s Avatar
    Just watch where you're putting it!

    Oh i know where to put it, lol
    kbz1960, Goldboot02 and Carjackd like this.
    03-17-15 01:00 PM
  25. kbz1960's Avatar
    Oh i know where to put it, lol
    TNWSS
    anon(9208252) and Carjackd like this.
    03-17-15 01:25 PM
11,789 ... 178179180181182 ...

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