[YuGiOhJCJ]

Hello,

I have a test application with a screen containing a button.
When I click the button (by pressing the trackpad key of my BlackBerry 9220), it opens a dialog.
Then when I press the ESCAPE key of my BlackBerry 9220, it closes the dialog and I am back on my screen.

Now, if I add to my screen a menu item, the behavior changes:
When I click the button (by pressing the trackpad key of my BlackBerry 9220), it opens a dialog.
Then when I press the ESCAPE key of my BlackBerry 9220, it closes the dialog and a popup screen menu is opened.

So, I would like to add my menu item but keeping the old behavior of my application after closing the dialog.

Any idea?

Thank you.
Best regards.

Here is the code:

import net.rim.device.api.ui.UiApplication;
import net.rim.device.api.ui.component.ButtonField;
import net.rim.device.api.ui.component.Dialog;
import net.rim.device.api.ui.container.MainScreen;
import net.rim.device.api.ui.Field;
import net.rim.device.api.ui.FieldChangeListener;
import net.rim.device.api.ui.MenuItem;
import net.rim.device.api.util.StringProvider;
public class TestApplication extends UiApplication
{
public TestApplication()
{
this.pushScreen(new TestScreen());
}
public static void main(String[] args)
{
TestApplication application = new TestApplication();
application.enterEventDispatcher();
}
}
final class TestScreen extends MainScreen implements FieldChangeListener
{
public TestScreen()
{
/*MenuItem myMenuItem = new MenuItem(new StringProvider("My menu item"), 0x230000, 0);*/
ButtonField myButtonField = new ButtonField("My button field");
myButtonField.setChangeListener(this);
this.add(myButtonField);
/*this.addMenuItem(myMenuItem);*/
}
public void fieldChanged(Field field, int context)
{
Dialog.alert("Test");
}
}

Here are some screenshots: